1/3(9x^-4y^5z)^2

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Solution for 1/3(9x^-4y^5z)^2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/3)*(9*x^-4*y^5*z)^2 = 0

27*x^-8*y^10*z^2 = 0 // : 27*y^10*z^2

x^-8 = 0

x należy do O

x belongs to the empty set

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